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What is the magnitude of your displacement when you follow directions that tell you to walk 225 m in one direction, make a 90° turn to the left and walk 350 m, then make a 30° turn to the right and walk 125 m?​

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LammettHash

Start by facing East. Your first displacement is the vector

d₁ = (225 m) i

Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,

d₂ = (350 m) j

Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,

d₃ = (125 m) (cos(60º) i + sin(60º) j )

d₃ ≈ (62.5 m) i + (108.25 m) j

The net displacement is

d = d₁ + d₂ + d₃

d ≈ (287.5 m) i + (458.25 m) j

and its magnitude is

|| d || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m

onyebuchinnaji

The magnitude of the displacement is 291.08 m            

From the given parameters;

  • initial displacement, x₁ = 225 m
  • second displacement, x₂ = 350 m at 90⁰ to the left
  • final displacement, x₃ = 125 m at 30⁰ to the right

Displacement is the shortest distance between the initial position and the final position.

From the image added, the magnitude of the displacement is length PQ.

Apply Pythagoras theorem, t o determine the magnitude of the displacement.

"check the image uploaded"

[tex](125 + x)^2 = 350^ 2 + 225^2\\\\(125 + x)^2 = 173,125\\\\125 + x = \sqrt{173125} \\\\125 + x = 416.08 \\\\x = 416.08 - 125\\\\x = 291.08 \ m[/tex]                              

Thus, the magnitude of the displacement is 291.08 m            

Learn more here: https://brainly.com/question/18033352                                            

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