Answer with a step-by-step explanation:
1) Making t as the subject.
[tex]\frac{5}{t} -2=s\\\\\frac{5}{t}=s+2\\\\5=t(s+2)\\\\\frac{5}{(s+2)} =\frac{t}{(s+2)} \\\\\frac{5}{(s+2)}=t[/tex]
2) Making r as the subject.
[tex]p = 3 + 2r\\\\p-3=2r\\\\\frac{(p-3)}{2} =\frac{2r}{2} \\\\\frac{(p-3)}{2} =r[/tex]
3) Making p as the subject.
[tex]t = 5p ^2 + 40\\\\t-40=5p^2\\\\\frac{(t-40)}{5} =p^2\\\\\sqrt{\frac{(t-40)}{5} } =p[/tex]
4) Making t as the subject.
[tex]u = \frac{t}{3} + 5\\\\u-5=\frac{t}{3}\\\\ 3(u-5)=t[/tex]
5) Making x as the subject.
[tex]w = x ^2 + y\\\\w-y=x^2\\\\\sqrt{(w-y)} =x[/tex]
