The expression (3 + i)(1+2i) can be written in the form a + bi, where a and b are integers. What are the values of a and b?

Answer:
Step-by-step explanation:
Given the complex expression, (3 + i)(1+2i) we are to expand it in the form a+bi as shown;
(3 + i)(1+2i)
= 3(1)+3(2i)+1(i)+i(2i)
= 3 + 6i + i + 2i²
= 3 + 71 + 2i²
According to complex notation i² = -1
;Substitute
= 3+7i+2(-1)
= 3 + 7i - 2
= 1 + 7i
Comparing 1+7i with a + bi
a = 1 and b = 7
The values of a and b are 1 and 7 respectively and this can be determined by using the arithmetic operations.
Given :
Expression -- (3 + i)(1+2i)
The following steps can be used to determine the values of 'a' and 'b':
Step 1 - Write the given expression.
= (3 + i)(1+2i)
Step 2 - Multiply 3 by (1 + 2i) and multiply i by (1 + 2i) in the above expression.
= 3 + 6i + i + 2(i[tex]\times[/tex]i)
Step 3 - The value of i[tex]\times[/tex]i = -1. So put the value (i[tex]\times[/tex]i) in the above expression.
= 3 + 6i + i - 2
Step 4 - Add 6i and i in the above expression.
= 3 + 7i -2
Step 5 - Subtract 2 from 3 in the above expression.
= 1 + 7i
Step 6 - Compare the above expression to a+bi.
a = 1
b = 7
So, the values of a and b are 1 and 7 respectively.
For more information, refer to the link given below:
https://brainly.com/question/2096984