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7.4 Code Practice: Question 2
Adjust the code you wrote for the last problem to allow for weighted classes. Add a parameter weighted ( 1 = yes, 0 = no) and then return the correct number for the GPA. Weighted classes get one extra point on the GPA value.

I could really use some help on this and 7.5 (I’ll ask that question for 7.5 later)

74 Code Practice Question 2 Adjust the code you wrote for the last problem to allow for weighted classes Add a parameter weighted 1 yes 0 no and then return the class=

Respuesta :

Cytokine

def GPAcalc(grade, weighted):

   grade = grade.lower()

   dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}

   if weighted == 1 and grade in dictionary:

       return "Your GPA score is: "+str(dictionary[grade] + 1)

   elif weighted == 0 and grade in dictionary:

       return "Your GPA score is : "+str(dictionary[grade])

   else:

       return "Invalid"

print(GPAcalc(input("Input a letter grade: "), int(input("Is it weigthed? (1= yes, 0= no)"))))

I modified the code a bit to cut down on the use of if and elif statements. If you need me to change it, I will. Best of luck.

MrRoyal

The program is an illustration of conditional statements.

Conditional statements are statements whose execution is dependent on its truth value.

The program in Python, where comments are used to explain each line is as follows:

#This initializes the dictionary

dict = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}

#This gets input for grade

grade = input().lower()

#This gets input for the weighted average

weighted = int(input())

#If the weighted average is 1, and the grade is in the dictionary

if weighted == 1 and grade in dictionary:

   #This prints the GPA score

   print("Your GPA score is: "+str(dict[grade] + 1))

#If the weighted average is 0, and the grade is in the dictionary

elif weighted == 0 and grade in dictionary:

   #This prints the GPA score

   print("Your GPA score is : "+str(dict[grade]))

#Otherwise

else:

   #The grade is invalid

   print("Invalid")

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