Answer:
( [tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] ) is closer to [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
[tex]\frac{2}{15}[/tex] + [tex]\frac{1}{3}[/tex] = [tex]\frac{2 + 5}{15}[/tex] = [tex]\frac{7}{15}[/tex]
[tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] = [tex]\frac{18-7}{21}[/tex] = [tex]\frac{11}{21}[/tex]
[tex]\frac{7}{15}[/tex] , [tex]\frac{1}{2}[/tex] , [tex]\frac{11}{21}[/tex]
LCD (2, 15, 21) = 210
[tex]\frac{98}{210}[/tex] , [tex]\frac{105}{210}[/tex] , [tex]\frac{110}{210}[/tex]
105 - 98 = 7
110 - 105 = 5 ⇒ [tex]\frac{11}{21}[/tex] is closer to [tex]\frac{1}{2}[/tex] ⇒ ( [tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] ) is closer to [tex]\frac{1}{2}[/tex]
