The limiting reagent : NH₃
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant
Reaction
4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)
mol NH₃ :
[tex]\tt \dfrac{4.5}{17}=0.265[/tex]
mol O₂ :
[tex]\tt \dfrac{15.8}{32}=0.494[/tex]
mol ratio
NH₃ :
[tex]\tt \dfrac{0.265}{4}=0.06625[/tex]
O₂ :
[tex]\tt \dfrac{0.494}{5}=0.0988[/tex]
Limiting reactants : NH₃ (smaller ratio)
The limiting reagent when a 4.50 g sample of ammonia is mixed with 15.80 g of oxygen is NH₃
The limiting reactant refers to the reactant that gets consumed first in a chemical reaction and thus it limits how much product can be created or developed. A method that can be used to determine limiting reactants that to divide the number of moles by their respective coefficients.
So,
For mol NH₃ :
[tex]= 4.5\div 17[/tex]
= 0.494
For mol O₂ :
[tex]= 15.8 \div 32[/tex]
= 0.494
For mol ratio
NH₃ :
[tex]= 0.265 \div 4[/tex]
= 0.06625
O₂ :
[tex]= 0.494 \div 5[/tex]
= 0.0988
Based on the above calculations we can say that it is NH₃
learn more about the oxygen here: https://brainly.com/question/19803828
