4.
For each equation, find a value for x that makes the equation true. Show your work on the next
page.
a.
x=3 = 12
b.
c.
Ex-3
d.
2x + 3 = 20
4 10
3
- 4x = -24
2(x - 4) = 10
-0.5x + 1.1 = -2.9
e.
f.

4 For each equation find a value for x that makes the equation true Show your work on the next page a x3 12 b c Ex3 d 2x 3 20 4 10 3 4x 24 2x 4 10 05x 11 29 e f class=

Respuesta :

Answer:

a) 36

b) 8.5

c) 5/2

d) 6

e) 9

f) 8

Step-by-step explanation:

a) [tex]x \div 3 =12[/tex]

Multiply both sides by 3

[tex]x \div 3 =12\\3*(x \div 3) = 12*3\\x=36[/tex]

b) [tex]2x+3=20[/tex]

Subtracting 3 from both sides

[tex]2x+3-3=20-3\\2x=20-3\\2x=17\\x=\frac{17}{2}\\x=8.5[/tex]

c) [tex]\frac{4}{3}x=\frac{10}{3}[/tex]

Multiply both sides by 3/4

[tex]\frac{4}{3}x*\frac{3}{4} =\frac{10}{3} *\frac{3}{4}\\x=\frac{5}{2}[/tex]

d) [tex]-4x=-24[/tex]

Divide both sides by -4

[tex]-4x=-24\\\frac{-4x}{-4}=\frac{-24}{-4}\\x=6[/tex]

e) [tex]2(x-4)=10[/tex]

Divide both sides by 2

[tex]2(x-4)=10\\\frac{2(x-4)}{2}=\frac{10}{2}\\x-4=5\\Adding \ 4 \ on \ both \ sides\\x-4+4=5+4\\x=9[/tex]

f) [tex]-0.5x+1.1=-2.9[/tex]

Subtracting 1.1 on both sides

[tex]-0.5x+1.1-1.1=-2.9-1.1\\-0.5x=-4\\Divide \ both \ sides \ by \ -0.5\\\frac{-0.5x}{-0.5}=\frac{-4}{-0.5}\\x=8[/tex]