Taking into account the Gay-Lussac's Law, the pressure will increase by a factor less than three.
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions against the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
In summary, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Mathematically, Gay-Lussac's law indicates that the ratio of pressure to temperature is constant:
[tex]\frac{P}{T} =k[/tex]
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]
In this case, a given mass of gas in a rigid container is heated from 100 ° C to 300 ° C, that is, it is heated from 373 ° K to 573 ° K. This indicates that the temperature is increasing by a factor less than three. Since pressure is directly proportional to temperature, pressure must increase in the same proportion.
Finally, the pressure will increase by a factor less than three.
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