Answer:
t>2.034s and t>0.154s
Step-by-step explanation:
Given the quadratic function h(t)=-16t^2+35t+5 which represents the height of the balloon, h, in feet t seconds after it is thrown.
To determine when the balloon is more than 10feet above the ground, we will substitute h = 10 into the expression to have;
h(t)=-16t^2+35t+5
-16t^2+35t+5>10
-16t^2+35t+5-10>0
16t^2-35t+5>0
Find t;
t > 35±√35²-4(16)(5)/2(16)
t>35±√1225-320/32
t>35±√905/32
t>35±30.08/32
t > 35+30.08/32 and t > 35-30.08/32
t>65.08/32 and t>4.92/32
t>2.034s and t>0.154s
Hence the balloon is more than 10feet above the ground at when t>2.034s and t>0.154s
