Answer:
[tex]Probability = \frac{45}{98}[/tex]
Step-by-step explanation:
Given
Represent travel guide with T and Fictions with F
[tex]T = 5[/tex]
[tex]F = 9[/tex]
Required
Determine the probability that one of both was selected
This implies that (1 travel guide and 1 fiction) or (1 fiction and 1 travel guide)
The probability is is calculated as thus:
[tex]Probability = P(T\ n\ F)\ or\ P(F\ n\ T)[/tex]
In probability, the above formula can be translated to
[tex]Probability = P(T) *P(F)\ +\ P(F) *P(T)[/tex]
[tex]Probability = \frac{n(T)}{Total} *\frac{n(F)}{Total}\ +\ \frac{n(F)}{Total} *\frac{n(T)}{Total}[/tex]
[tex]Probability = \frac{5}{5 + 9} *\frac{9}{5 + 9} +\frac{9}{5 + 9} *\frac{5}{5 + 9}[/tex]
[tex]Probability = \frac{5}{14} *\frac{9}{14} +\frac{9}{14} *\frac{5}{14}[/tex]
[tex]Probability = \frac{45}{196} +\frac{45}{196}[/tex]
[tex]Probability = \frac{90}{196}[/tex]
[tex]Probability = \frac{45}{98}[/tex]
