Step 1: We start by writing the equation of the line in slope-intercept form by solving for b.
[tex]-5 = 3(-1) + b\\\\-5 = -3 + b\\\\-2 = b\\[/tex]
Step 2: Now we set up the equation of the line in slope-intercept form.
[tex]y = 3x - 2[/tex]
Step 3: We can now convert the above equation from slope-intercept form to standard form.
[tex]y = 3x - 2\\\\-3x + y = -2\\\\-3x + y + 2 = 0[/tex]
The equation of the line in standard form is: D: -3x + y + 2 = 0.