Answer:
B
Step-by-step explanation:
We have the compound inequality:
[tex]5x+7\leq-3 \text{ or } 3x-4\geq 11[/tex]
Since this is an “OR” inequality, we can solve each inequality individually. So:
1)
We have:
[tex]5x+7\leq-3[/tex]
Subtract 7 from both sides:
[tex]5x\leq -10[/tex]
Divide both sides by 5:
[tex]x\leq-2[/tex]
So, the first solution is above.
2)
We have:
[tex]3x-4\geq 11[/tex]
Add 4 to both sides:
[tex]3x\geq15[/tex]
Divide both side by 3:
[tex]x\geq5[/tex]
Our second solution is above.
Therefore, our solution is:
[tex]x\leq -2 \text{ or } x\geq5[/tex]
Since our original inequality is “OR,” our solution set remains an “OR.”
Hence, our answer is B.
