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A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?

A. 0N
B. 200N
C. 5000N
D. 10000N

Respuesta :

Answer: 5000N

Explanation:

The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N

The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C).  

The gravitational force exerted on the satellite by the planet will be equal to the planet's gravity, which is equal to the centripetal force, so:

[tex] F_{g} = F_{c} = ma_{c} [/tex]

Where:

m: is the mass of the satellite = 1000 kg

[tex]a_{c}[/tex]: is the centripetal acceleration = 5 m/s²

The, the force acting on the satellite is:

[tex] F_{c} = ma_{c} = 1000 kg*5 m/s^{2} = 5000 N [/tex]

Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).

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I hope it helps you!

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