Respuesta :
consecutive integers are 1 apart
they are
x,x+1,x+2
add to 15
x+x+1+x+2=15
3x+3=15
minus 3 both sides
3x=12
divide both sides by 3
x=4
x+1=5
x+2=6
they are 4,5,6
they are
x,x+1,x+2
add to 15
x+x+1+x+2=15
3x+3=15
minus 3 both sides
3x=12
divide both sides by 3
x=4
x+1=5
x+2=6
they are 4,5,6
Our three consecutive integers can be represented as
X → first integer
X + 1 → second integer
X + 2 → third integer
If the sum of our three consecutive integers is 15, our equation will read...
X + X + 1 + X + 2 = 15
Now, we can simplify on the left. Once we simplify, our equation will now read
3x + 3 = 15
-3 -3 ← subtract 3 from both sides
3x = 12 ← divide both sides by 3
X = 4
X → first integer 4
X + 1 → second integer 5
X + 2 → third integer 6
Therefore, the 3 consecutive integers are 4, 5, and 6.