Answer:
The equation in point-slope form is: [tex]\mathbf{y=\frac{1}{11}x-\frac{5}{11} }[/tex]
Step-by-step explanation:
We need to find equation of line in point slope form that passes through points (5,0) and (-6, -1).
The general equation of point slope form is: [tex]\mathbf{y-y_1=m(x-x_1)}[/tex]
where m is the slope of line.
We need to know Slope m
Finding Slope m
Finding Slope m using formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
We have [tex]x_1=5, y_1=0, x_2=-6 \ and \ y_2=-1[/tex]
Putting values and finding slope
[tex]Slope=\frac{-1-0}{-6-(5)}\\Slope=\frac{-1}{-6-5}\\Slope=\frac{-1}{-11}\\Slope=\frac{1}{11}[/tex]
So , slope m is: [tex]\mathbf{m=\frac{1}{11}}[/tex]
Using point (5,0) and slope m =1/22 the equation of point-slope form is:
[tex]y-y_1=m(x-x_1)\\y-0=\frac{1}{11} (x-5)\\y=\frac{1}{11}x-\frac{5}{11}[/tex]
So, the equation in point-slope form is: [tex]\mathbf{y=\frac{1}{11}x-\frac{5}{11} }[/tex]
