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A steel tank contains carbon dioxide at a pressure of 13.0 atm when the temperature is 34oC. What will be the internal gas pressure when the tank and its contents are heated to 100oC

A steel tank contains carbon dioxide at a pressure of 130 atm when the temperature is 34oC What will be the internal gas pressure when the tank and its contents class=

Respuesta :

quasarJose

Answer:

D. 15.8atm

Explanation:

Given parameters:

Initial pressure = 13atm

Initial temperature  = 34°C = 34 + 273  = 307K

Final temperature  = 100°C = 100 + 273  = 373K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.

The expression is shown mathematically below;

        [tex]\frac{P_{1} }{T_{1} }[/tex]   = [tex]\frac{P_{2} }{T_{2} }[/tex]

P and T pressure and temperature values

1 and 2 are initial and final states

 Insert the parameters and solve for T₂;

    [tex]\frac{13}{307}[/tex]   = [tex]\frac{P_{2} }{373}[/tex]  

        P₂  = 15.8atm

Cricetus

The final pressure will be "15.8 atm".

According to the question,

Initial pressure,

[tex]P_1 = 13.0 \ atm[/tex]

Initial temperature,

[tex]T_1 = 34+273[/tex]

    [tex]= 307 \ k[/tex]

Final temperature,

[tex]T_2 = 100+273[/tex]

    [tex]= 372 \ k[/tex]

By using the Gay-Lussac's law of pressure and temperature, we get

→     [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

or,

→     [tex]P_2 = \frac{P_1\times T_2}{T_1}[/tex]

By substituting the values, we get

→          [tex]= \frac{13.0\times 373}{307}[/tex]

→          [tex]= 15.8 \ atm[/tex]

Thus the response above is right.

Learn more:

https://brainly.com/question/24191545

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