9514 1404 393
Answer:
- 0.70
- yes
Step-by-step explanation:
1. P(≥30 | B) = P(≥30 & B)/P(B)
P(≥30 | B) = 0.21/0.30 = 0.70
The probability that a B student did at least 30 minutes of homework is 0.70.
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2. The probability that any student did at least 30 minutes of homework is shown in the column a the right end of the table: 0.70. This is the same as the probability that a B student did at least 30 minutes of homework. That is ...
P(≥30 | B) = P(≥30)
Hence, the events "at least 30 minutes of homework" and "B student" are independent.