in the circle shown, chords AC and BD intersect at E . if AE=8, EC=6, and BE=4. how long is DE?
10
12
14
16

Answer:
[tex] DE = 12 [/tex]
Step-by-step explanation:
Given:
AE = 8,
EC = 6,
BE = 4.
Required:
Length of DE
SOLUTION:
According to the Intersecting Chords Theorem, [tex] DE \times BE = AE \times EC [/tex]
Plug in the values into the equation. We would have:
[tex] DE \times 4 = 8 \times 6 [/tex]
[tex] DE \times 4 = 48 [/tex]
Divide both sides by 4
[tex] DE = \frac{48}{4} [/tex]
[tex] DE = 12 [/tex]