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Use the product-to-sum identities to rewrite the following expression as a sum or difference.

2cos(2x)cos(2x)

Respuesta :

adrianabazan
Answer:

= cos4x

Explanation:

cosAcosB = [cos(A-B)+cos(A+B)]

Given: 2cos(2x)cos(2x)

= 2[cos(2x-2x)+cos(2x+2x)]

= 2cos4x^2

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