Answer:
[tex]\dfrac{\$1000+\$20x}{x} \leq \$25[/tex]
Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = [tex]x[/tex]
Cost of food for [tex]x[/tex] people = [tex]\$20x[/tex]
Total cost = $1000 + [tex]\$20x[/tex]
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:
[tex]\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200[/tex]
Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.
