The statement that would be true if triangle EFI and triangle GFH are similar triangles is: [tex]\mathbf{ \frac{FH}{FI} = \frac{HG}{IE} }[/tex]
Recall:
Similar triangles will always have the same shape but different sizes.
The corresponding side lengths of two triangles that are similar are always proportional.
All three angles in one triangle are all congruent to all three corresponding angles in the other triangle it is similar to.
If triangle EFI and triangle GFH are similar, therefore:
<E ≅ <G; <F ≅ <F; <I ≅ <H
[tex]\frac{GF}{EF} = \frac{HG}{IE} = \frac{FH}{FI}[/tex]
Therefore, the statement that would be true if triangle EFI and triangle GFH are similar triangles is: [tex]\mathbf{ \frac{FH}{FI} = \frac{HG}{IE} }[/tex]
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