Answer: (2): 25 N.
Explanation:
We know that two forces act concurrently on the same object.
One force has a magnitude of 30 N, so the first force can be written as:
F = (fx, fy) such that:
30N = √(fx^2 + fy^2)
And other force of 20 N, let's call it G.
G = (gx, gy)
Such that:
20 N = √(gx^2 + gy^2)
Now, the maximum possible resultant force is when both forces point in the same direction.
Then we can directly add them; G + F = 20N + 30N = 50N
And the minimum resultant force is when both forces point in opposite directions, then we can directly subtract: F - G = 30N - 20N = 10N.
Then the resultant force, F', will be:
10N ≤ F' ≤ 50N.
The only option in that range is the second option, (2) 25N.