three numbers have a sum of 112. The first number is twice the second, and the third number is twice the first. What is the smallest of the three numbers?

Respuesta :

Answer:

The second number is the smallest of the three numbers with

value n = 16.

Step-by-step explanation:

Let n represent the second number, then the first number is 2n and the third number is 4n.

so

[tex]n+2n+4n=112[/tex]

Solving for n

[tex]n+2n+4n=112[/tex]

[tex]7n=112[/tex]

[tex]\frac{7n}{7}=\frac{112}{7}[/tex]

[tex]n=16[/tex]

As n = 16 is the second number.

The first number = 2n = 2(16) = 32

The third number = 4n = 4(16) = 64

Therefore, the second number is the smallest of the three numbers with value n = 16.