Respuesta :
Answer: E=15
There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.
Step-by-step explanation:
This can be obtained by after a simple counting of number from 2020 and 2400 as follows:
The first set of integers are:
2345, 2346, 2347, 2348, and 2349.
Therefore, there are 6 integers in first set.
The second set of integers are:
2356, 2357, 2358, and 2359.
Therefore, there are 4 integers in second set.
The third set of integers are:
2367, 2368, and 2369.
Therefore, there are 3 integers in third set.
The fourth set of integers are:
2378, and 2379.
Therefore, there are 2 integers in fourth set.
The fifth and the last set of integer is:
2389
Therefore, there is only 1 integers in fifth set.
Adding all the integers from each of the set above, we have:
Total number of integers = 6 + 4 + 3 + 2 + 1 = 15
Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.
Sorry if it is incorrect
The total number of integers between 2020 and 2400 have four distinct digits arranged in increasing order is 15.
Given :
Numbers -- 2020 and 2400
The following steps can be used in order to determine the total number of integers between 2020 and 2400 have four distinct digits arranged in increasing order:
Step 1 - According to the given data, there are two numbers 2020 and 2400.
Step 2 - So, the integers having four distinct digits arranged in increasing order are:
2345, 2346, 2347, 2348, 2349, 2356, 2357, 2358, 2359, 2367, 2368, 2369, 2378, 2379, and 2389.
Step 3 - So, the total number of integers between 2020 and 2400 have four distinct digits arranged in increasing order is 15.
For more information, refer to the link given below:
https://brainly.com/question/25834626
