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A ships initial position is 25 km east of the origin. What is the ship’s final position if it sails at a constant velocity of 42 km/h east in exactly 1.5 h? (Note: answer in km)

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ibadullahqureshi01

Answer:

88km E

Explanation:

25 km is added already

then if we take the formula of speed(V)

V=d/t

and rearrange it to subject d (distance)

d= V x t

we get

d= 42km/h x 1.5hrs

we get

63 km

now if we add the already travelled 25 km to this additional distance

63km + 25km = 88km

Thus the final distance traversed by the ship from its origin is

88km E

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