Answer:
[tex]x=-\sqrt2\text{ or } x=\sqrt2[/tex]
Step-by-step explanation:
We have:
[tex]7+2x^2=11[/tex]
To solve, we will isolate the x variable. Therefore, subtract 7 from both sides:
[tex]2x^2=4\\[/tex]
Divide both sides by 2:
[tex]x^2=2[/tex]
Take the square root of both sides. Since we’re taking an event root, we will need plus/minus. Therefore:
[tex]x=\pm\sqrt2[/tex]
Therefore, our solutions are:
[tex]x=-\sqrt2\text{ or } x=\sqrt2[/tex]
