Answer:
[tex]\Delta=144[/tex]
Step-by-step explanation:
For a quadratic in standard form, the discriminant is given by:
[tex]\Delta=b^2-4ac[/tex]
We have the equation:
[tex]4x^2-8x-5=0[/tex]
Hence, our a=4; b=-8; and c=-5.
Substituting into our formula, we acquire:
[tex]\Delta=(-8)^2-4(4)(-5)[/tex]
Evaluate:
[tex]\Delta=64+80[/tex]
Add:
[tex]\Delta=144[/tex]
Therefore, our discriminant is 144.
Notes:
Since our discriminant is a positive value, this tells us that our quadratic has two real roots.
