Answer:
[tex]x = \frac{3}{4} + \frac{ \sqrt{105} }{4} \: \: , \: \: \: x = \frac{3}{4} - \frac{ \sqrt{105} }{4} \\ [/tex]
Step-by-step explanation:
2x² - 3x - 12 = 0
Using the quadratic formula which is
[tex]x = \frac{ - b \pm\sqrt{ {b}^{2} - 4ac} }{2a} \\ [/tex]
From the question
a = 2 , b = - 3 , c = - 12
So we have
[tex]x = \frac{ - - 3\pm \sqrt{ ({ - 3})^{2} - 4(2)( - 12)} }{2(2)} \\ = \frac{3\pm \sqrt{9 + 96} }{4} \\ = \frac{3\pm \sqrt{105} }{4} \: \: \: \: \: \: [/tex]
Separate the solutions
We have the final answer as
[tex]x = \frac{3}{4} + \frac{ \sqrt{105} }{4} \: \: , \: \: \: x = \frac{3}{4} - \frac{ \sqrt{105} }{4} \\ [/tex]
Hope this helps you