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A balloon contains 3300 mL of helium gas at 63 °C. What is the final volume, in milliliters, of the gas when the temperature changes to each of the following, if pressure and amount of gas do not change? Part A 78 C Express your answer to two significant figures and include the appropriate units. UA Vi= Value Units​

Respuesta :

ardni313

The final volume : 3.4 L

Further explanation

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

V₁=3300 ml

T₁=63 + 273=336 K

T₂=78+273=351 K

the final volume :

[tex]\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{3300\times 351}{336}\\\\V_2=3447.3~ml\rightarrow 2~sig.~fig.\rightarrow 3.4~L[/tex]

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