Answer:
V = 131.23 L
Explanation:
Given data:
Moles of CO₂ = 5.3 mol
Temperature = 28°C
Pressure = 0.998 atm
Volume occupied = ?
Solution:
Formula:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
28+273 = 301 K
0.998 atm ×V = 5.3 mol × 0.0821 atm.L/ mol.K × 301 K
V = 130.97 atm.L / 0.998 atm
V = 131.23 L
