(2 points) How many grams of K2SO4 are present in 25.0 mL of 7.00 % (m/v) solution?
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Respuesta :

Mass of K₂SO₄ : 1.75 g

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

volume of solution = 25 ml

% (m/v)=7%

mass of K₂SO₄ :

[tex]\tt \%m/v=\dfrac{mass~of~solute}{volume~of~solution}\times 100\%\\\\7\%=\dfrac{mass~K_SO_4}{25}\times 100\%\\\\mass~K_2SO_4=7\times 25\div 100=1.75~g[/tex]