Answer:
0
Step-by-step explanation:
We are given that
[tex]G(x)=3x+1[/tex]
We have to find the value of [tex]G^{-1}(1)[/tex]
To find the value of [tex]G^{-1}(1)[/tex] we will find first [tex]G^{-1}(x)[/tex]
Let [tex]y=G(x)=3x+1[/tex]
[tex]3x=y-1[/tex]
[tex]x=\frac{1}{3}(y-1)[/tex]
Now, replace x by y and y replace by x
Then, we get
[tex]y=\frac{1}{3}(x-1)[/tex]
Now, substitute [tex]G^{-1}(x)=y[/tex]
[tex]G^{-1}(x)=\frac{1}{3}(x-1)[/tex]
Now, substitute x=1
Then, we get
[tex]G^{-1}(1)=\frac{1}{3}(1-1)=0[/tex]
Hence, the value of [tex]G^{-1}(1)=0[/tex]
