Karen calculates the volume of cylinder A with a radius of 3 inches, and a height of 6 inches. The volume of this cylinder is 54π in3. Cylinder B also has a radius of 3 inches, but the height is doubled. What is the relationship between the volumes of the two cylinders?

Respuesta :

the volume of B is twice that of A
if Vb=2hpir^2
and Va=hpir^2

compare
2hpir^2
hpir^2

twic as big

Volume of B is 2 times that of Volume of A

Answer:

[tex]2(\text{Volume of cylinder A})= \text{Volume of cylinder B }[/tex]

Step-by-step explanation:

Cylinder A:

Radius = 3 inches

Height = 6 inches

Volume = [tex]54\pi inches^3[/tex]

Cylinder B:

We are given that Cylinder B also has a radius of 3 inches, but the height is doubled.

Radius = 3 inches

Height = [tex]2 \times 6 =12[/tex] inches

Volume of cylinder B = [tex]\pi r^{2}  h[/tex]

                               = [tex]\pi (3)^{2} \times 12[/tex]  

                               = [tex]108 \pi inches^3[/tex]  

Thus the volume of cylinder B is 108π cubic inches

Volume of Cylinder A = 54 π cubic inches

Since [tex]2(54\pi )=108\pi[/tex]

So, twice the volume of cylinder A = Volume of cylinder B

[tex]2(\text{Volume of cylinder A})= \text{Volume of cylinder B }[/tex]

Hence the relationship between the volumes of the two cylinders is [tex]2(\text{Volume of cylinder A})= \text{Volume of cylinder B }[/tex]