Respuesta :
Volume in liters:
5.00x10² mL / 1000 => 0.5 L
Molar mass KI => 166.0028 g/mol
Mass KI = volume x molar mass x molarity
Mass KI = 0.5 x 166.0028 x 2.80
= 232.40392 g of KI
hope this helps!
5.00x10² mL / 1000 => 0.5 L
Molar mass KI => 166.0028 g/mol
Mass KI = volume x molar mass x molarity
Mass KI = 0.5 x 166.0028 x 2.80
= 232.40392 g of KI
hope this helps!
Explanation:
Molarity is the number of moles per liter of solution. Whereas number of moles is defines as mass divided by molar mass.
Therefore, Molarity = [tex]\frac{mass}{molar mass \times volume of solution}[/tex]
Since, it is given that molarity is 2.80 M, volume is 500 ml or 0.5 L, and molar mass of KI is 166 g/mol.
Hence, mass = [tex]Molarity \times molar mass \times volume of solution}[/tex]
= [tex]2.80 mol/L \times 166 g/mol \times 0.5 L[/tex]
= 232.4 g
Thus, mass of KI is 232.4 g which is required to prepare 5.00 X10^2 mL of a 2.80 M solution.