Respuesta :
if PLAN A is cheaper than PLAN B then,
P (A) < P (B)
30+0.01t < 20+0.05t (subtract 0.05t from both sides)
29.95-0.04t < 19.95 (subtract 29.95 from both sides)
-0.04t < -10 (divide both sides by -0.04)
t > 250
So plan A is cheaper than plan B when you send more than 250 texts.
Hope it helps.
P (A) < P (B)
30+0.01t < 20+0.05t (subtract 0.05t from both sides)
29.95-0.04t < 19.95 (subtract 29.95 from both sides)
-0.04t < -10 (divide both sides by -0.04)
t > 250
So plan A is cheaper than plan B when you send more than 250 texts.
Hope it helps.
Answer:
Minimum number of messages to be sent is 251 for Plan A to be cheaper than Plan B.
Step-by-step explanation:
Let the text messages needed to be sent in order for Plan A to be cheaper than Plan B be N
Therefore total cost of sending text messages in case of Plan A is
[tex]C_A=\$ (30+0.01N)[/tex]
and total cost of sending text messages in case of Plan B is
[tex]C_B=\$ (20+0.05N)[/tex]
Now for Plan A to be cheaper than Plan B , [tex]C_A < C_B[/tex]
[tex]\therefore (30+0.01N)< (20+0.05N)=>N> 250[/tex]
Thus for Plan A to be cheaper than Plan B more than 250 messages needed to be sent . Minimum number of messages to be sent is 251 for Plan A to be cheaper than Plan B.