Amandieshaylena
contestada

A tub of water is emptied at a rate of 3 gallons per minute. the equation y –12 = –3(x – 1) models the amount of water remaining, where x is time (in seconds) and y is the amount of water left (in gallons). analyze the work shown below to determine the initial amount of water. 1. solve for the y-variable. y – 12 = –3(x – 1) y – 12 = –3x 3 y = –3x 15 2. write the equation using function notation. f(x) = –3x 15

Respuesta :

GamingMathNerd
if you plot 3,12 on a graph and go move to the left one and up one untill the x axis is zero you will land on five. so the amount the tub started with is 15
calculista

Let

x-------> is the time in seconds

y------> is the amount of water left in gallons

we have

[tex] y -12 = -3(x - 1) [/tex]

solve for y

[tex] y -12 = -3x+3 [/tex]

Add [tex] 12 [/tex] to both sides

[tex] y -12+12 = -3x+3+12 [/tex]

[tex] y = -3x+15 [/tex]

[tex] f(x) = -3x+15 [/tex] ------> function notation

we know that

The initial amount of water is for [tex] x=0 [/tex]

So

substitute the value [tex] x=0 [/tex] in the function

[tex] f(x) = -3x+15 [/tex]

[tex] f(0) = -3*0+15 [/tex]

[tex] f(0) = 15 gal [/tex]

therefore

the answer is

The initial amount of water is [tex] 15 gal [/tex]

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