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The point (21, 32) is on a line with slope 1.5
a. Write the equation of the line.
b. What are the coordinates of another point on the line?

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hangingbyathread
Ok so for this question, you have to draw a graph to help. I'm doing the numbers by 2. You plot the points (21,32) on the graph then after that plot the points by the slope. What I'm trying to say by that is: 1.5 as a fraction is 3/2. so you count from that point by going 3 numbers up (or squares if on a graph if it makes more sense) then count 2 squares to the right and you continue doing that after every point you make (if there's no space to go up the graph the n you can go down by just counting 3 down then counting 2 to the LEFT)

I don't have graph paper on me so I can't really tell you the y-intercept because it might be not accurate (thats the number after the slope or "b" in the formula y=mx+b) How to find that is: when you follow the steps above you're going to hit the y-axis (vetical line) when you have an exact point hitting the y-axis (it should be right on that line ) then that's your number

Equation: y=1.5x+ (insert y-axis number here)
The coordiantes of another point is on the line (u can pick any)

Answer:

a) Equation of line:

[tex]y = 1.5x + 0.5[/tex]

b) Another point on line = (-0.333,0)

Step-by-step explanation:

We are given the following information in the question:

Slope of line = 1.5

Point(21, 32) lies on the line.

The equation of straight line is given by the equation:

[tex]y-y_0 = m(x-x_0)[/tex]

where m is the slope of the line and [tex](x_0,y_0)[/tex] is a point that lies on the line.

Putting the values, we get,

[tex]y - 32 = 1.5(x-21)\\y-32 = 1.5x - 31.5\\y = 1.5x - 31.5 + 32\\y = 1.5x + 0.5[/tex]

The above is the required equation of the line.

To find another point on line, we put y = 0:

[tex]0 = 1.5x + 0.5\\1.5x = -0.5\\\\x = \displaystyle\frac{-0.5}{1.5} = -0.333[/tex]

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