Respuesta :
Answer:
The impulse is 21.41 kg-m/s.
Explanation:
Given that,
Mass of stone = 2.50 kg
Height = 3.75 m
We need to calculate the time
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
Where, s = height
u = initial speed
t = time
Put the value in the equation
[tex]3.75=0+\dfrac{1}{2}\times9.8\times t^2[/tex]
[tex]t^2=\dfrac{3.75\times2}{9.8}[/tex]
[tex]t=\sqrt{\dfrac{3.75\times2}{9.8}}[/tex]
[tex]t=0.874\ sec[/tex]
We need to calculate the impulse
Using formula of impulse
[tex]J=F\times t[/tex]
[tex]J=mg\times t[/tex]
Put the value into the formula
[tex]J=2.50\times9.8\times0.874[/tex]
[tex]J=21.41\ kg-m/s[/tex]
Hence, The impulse is 21.41 kg-m/s.
The impulse gravity impart to this stone from the instant it is dropped until it hits the ground is 21.41 kg-m/s.
What is an impulse?
The impulse is defined as the effect of the force over a time. Like if you fall in a hard surface then force will be higher as compared to if you fall on a soft net. In soft net, the time increases and the effect of force decreases.
It is given that,
Mass of stone = 2.50 kg
Height = 3.75 m
We need to calculate the time
Using equation of motion
[tex]s=ut + \frac{1}{2} at^2[/tex]
Where, s = height
u = initial speed
t = time
Put the value in the equation
[tex]3.75=0+\frac{1}{2} \times 9.8\times t^2[/tex]
[tex]t=\sqrt{\dfrac{3.75\times 2}{9.8}[/tex]
[tex]t=0.874\ sec[/tex]
We need to calculate the impulse
Using formula of impulse
[tex]J=F\times t[/tex]
[tex]J=mg\times t[/tex]
Put the value into the formula
[tex]J=2.5\times 9.8\times 0.874[/tex]
[tex]J=21.41 \ kg-\frac{m}{s}[/tex]
Hence,the impulse gravity impart to this stone from the instant it is dropped until it hits the ground is 21.41 kg-m/s.
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