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Chris Nazarro had total travel expenses of $872. His transportation cost was $136. The hotel cost was $210 and business materials cost $500. If his lunch cost 30% of his dinner, how much was dinner to the nearest cent?

Respuesta :

total travel expenses of $872
transportation cost was $136, the hotel cost was $210 and business materials cost $500, total of these 3: $136 + $210 + $500 = $846

$872 - $ 846 = $26

So his lunch and dinner cost $26
But his lunch cost 30% of his dinner
Lets x is dinner cost
Lunch 30% of dinner cost = 0.3x
x + 0.3x = $26
1.3x = $26
x = $26/1.3
x = $20

So dinner cost $20
Lunch: 0.3x = 0.3 (20)  = $6