knowing that 33 can only be the product of 1 and 33 or 11 and 3, the answer is 11 and 3 since 11-3 = 8
but from an algebraic stand point here is how you solve it
make x be one number and y be the other. You know
x-y = 8 and
x * y = 33
solve either equation for x or y, I will choose the first one and solve for x
x - y = 8
x = y+8
now substitute that value of x in the second equation
x* y = 33
(y+8) * y = 33
y^2 + 8y = 33
make the equation equal to 0
y^2 + 8y - 33 = 0
now factor the equation
(y+11) (y-3) = 0
your 2 solutions are 3 and -11, since the question says there are positive numbers, the solution for y is 3
plug the y value (3) into either equation above and solve for x
x - 3 = 8
x = 11
