Respuesta :

(3x - 4) + 5
= 3x + 1

it's impossible to compare 3x + 1 to 27??
when
|a|=b
assume
a=b and
-a=b
for asbsolute value
|a|≤b
assume
a≤b
a≥-b

|3x-4|+5≤27
minus 5 both sides
|3x-4|≤22
so
3x-4≤22
3x-4≥-22

3x-4≤22
3x≤26
x≤26/3

3x-4≥-22
3x≥-18
x≥-6

combine
x≥-6 or x≤26/3
anything in those 2 ranges are the answer
basically
anything in the range, r, such that
-6<r<26/3

x≥-6 or x≤26/3 is answer