Ilovemyself80 Ilovemyself80

07-10-2016
Mathematics

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Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1

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apologiabiology apologiabiology

07-10-2016

easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1

f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10

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Аноним Аноним

07-10-2016

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