Answer:
49.49%
Step-by-step explanation:
volume of liquid in the flask= 200 cm^3
radius of the flask = 3 cm
height of the flask= 12 cm
volume of flask is given by = [tex]\pi\times r^2\times h[/tex]
putting values and solving we get =396 cm^3
therefore the volume unfilled= 396-200= 196cm^3
therefore % of volume unfilled= 196/396*100= 49.49%
