contestada

Hector placed new floor tile in his regular kitchen. The kitchen is 9 feet 9 inches long and 7 feet 4 inches wide. Hector paid $50 for tiles to cover the entire floor. What was the cost to tile each square foot of his kitchen? Round your answer to the nearest cent.

Respuesta :

abidemiokin

Answer:

29cents

Step-by-step explanation:

Given the dimension of the Kitchen as;

Length = 9feet 9inches

Width = 7feet 4inches

Since 1inch = 0.833ft

Length = 9+(9×0.833) = 9+7.497=16.497feet

Width = 7+(4×0.833) = 7+3.332 = 10.332feet

Area of the kitchen in ft² = 16.497×10.332= 170.447004ft²

Since Hector pays $50 to cover the floor, hence;

$50 = 170.447004ft²

x = 1ft²

Cross multiply

170.447004x= 50

x = 50/170.447004

x= $0.2933

x = 29.33cents

Cost of each square foot of his kitchen will be 29cents to nearest cent

Otras preguntas