Answer:
The solutions to the system of equations are:
[tex]x=\frac{1}{2},\:y=5[/tex]
Step-by-step explanation:
Given the system of the equations
[tex]\begin{bmatrix}4x-3y=-13\\ -2x+y=4\end{bmatrix}[/tex]
Isolate x for for 4x-3y=-13
[tex]4x-3y=-13[/tex]
[tex]4x=-13+3y[/tex]
Divide both sides by 4
[tex]x=\frac{-13+3y}{4}[/tex]
substitute y=5
[tex]x=\frac{-13+3\cdot \:5}{4}[/tex]
[tex]x=\frac{1}{2}[/tex]
The solutions to the system of equations are:
[tex]x=\frac{1}{2},\:y=5[/tex]
