Factoring trinomials and difference of squares. I need to understand the steps.

Answer:
Factoring the term [tex]3x^2-75[/tex] we get [tex]\mathbf{3(x+5)(x-5)}[/tex]
Step-by-step explanation:
We need to solve the polynomial: [tex]3x^2-75[/tex]
First we see that 3 is common term, so taking 3 as common
[tex]3(x^2-25)[/tex]
We know that 25 = 5x5 = 5²
So, replacing 25 with 5²
[tex]3(x^2-5^2)[/tex]
We know that, [tex]a^2-b^2=(a-b)(a+b)[/tex]
Applying this in our equation: [tex]x^2-5^2=(x+5)(x-5)[/tex]
[tex]3(x+5)(x-5)[/tex]
So, factoring the term [tex]3x^2-75[/tex] we get [tex]\mathbf{3(x+5)(x-5)}[/tex]