Respuesta :

ardni313

Mass of H₂ needed to react with O₂ : 1.092 g

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Reaction

O₂(g) + 2H₂(g) → 2H₂O(g)

mass of O₂ : 8.75 g

mol O₂(MW=32 g/mol) :

[tex]\tt \dfrac{8.75}{32}=0.273[/tex]

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

[tex]\tt \dfrac{2}{1}\times 0.273=0.546[/tex]

Mass H₂ (MW=2 g/mol) :

[tex]\tt 0.546\times 2=1.092~g[/tex]

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

[tex]\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2O[/tex]

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of oxygen = [tex]\rm \dfrac{8.75}{32}[/tex]

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles [tex]\times[/tex] molecular weight

Mass of hydrogen = 0.54 [tex]\times[/tex] 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

For more information about the mass to react, refer to the link:

https://brainly.com/question/23409112

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