The probability that the following parents, AABbCc × AaBbCc, will produce an AaBbCc offspring - 1/8
Independent assortment occurs spontaneously when alleles of at least two genes are assorted independently into gametes. Consequently, the allele inherited by one gamete does not affect the allele inherited by other gametes
AABbCc × AaBbCc -> AaBbCc
AA Aa AA Aa BB Bb Bb bb CC Cc Cc cc
↓ ↓ ↓
2/4 2/4 2/4
- In the case of gene A, out of the 4 probable allelic combinations, 2 will be Aa so the probability is 2/4.
- In the case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.
- In the case of gene C, out of the 4 probable allelic combinations,, 2 will be Cc so the probability is 2/4.
So, the total probability of getting AaBbCc = 2/4 x 2/4 x 2/4 = 1/8.
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