A mixture of hydrocarbons contains 34.8% heptane, C7H16, 10.1% nonane, C9H20, and 55.1% octane, C8H18. The mixture is combusted in an excess of oxygen. What mass of CO2 is generated from the combustion of 17.0 kg
of the mixture?
:

Respuesta :

Mass of CO₂ generated from the combustion : 14.277 kg

Further explanation

Mass Heptane : 0.348 x 17 = 5.916 kg

mass C in Heptane (MW=100.21 g/mol) :

[tex]\tt \dfrac{7.12}{100.21}\times 5.916=4.959~kg[/tex]

Mass Nonane : 0.101 x 17 = 1.717 kg

mass C in Nonane (MW=128.2 g/mol) :

[tex]\tt \dfrac{9.12}{128.2}\times 1.717=1.446~kg[/tex]

Mass Octane : 0.551 x 17 = 9.367 kg

mass C in Otane (MW=114.23 g/mol) :

[tex]\tt \dfrac{8.12}{114.23}\times 9.367=7.872~kg[/tex]

Total mass produced :

4.959+1.446+7.872=14.277 kg

The branch of science which deals with chemicals is called chemistry.

The correct answer is 14.277 kg

The calculation part is as follows:-

  • Mass Heptane : [tex]0.348 * 17 = 5.916 kg[/tex]
  • Mass C in Heptane (MW=100.21 g/mol) :

[tex]\frac{7.12}{100.21} *5.916 = 4.959kg[/tex]

  • Mass Nonane : [tex]0.101 * 17 = 1.717 kg[/tex]
  • Mass C in Nonane (MW=128.2 g/mol) :

[tex]\frac{9.12}{128.2} *1.717 =1.446kg[/tex]

  • Mass Octane : [tex]0.551 * 17 = 9.367 kg[/tex]
  • Mass C in Otane (MW=114.23 g/mol) :

[tex]\frac{8.12}{114.23}*7.872 kg[/tex]

Total mass-produced is

[tex]4.959+1.446+7.872=14.277 kg[/tex]

Hence, the correct answer is - 14.277kg.

For more information, refer to the link:-

https://brainly.com/question/25026730