A batter hits a ball at 25 m/a 37 degrees above the horizon. (Part A) how long is the ball in the air? (Part b) how far does it travel?

Explanation:
we know
v=u-gt
At max height v=0
uy=usin30
now,25sin37=gt
15.07/9.8=t
t=1.53s to reach max height now to come on ground it takes same time
so time taken t=3.07s
We know ,range=ucos37×t
=25cos37×3.07
max distance=61.3meter